Design Article
Power Tip: Snubbing the forward converter
Robert Kollman, Texas Instruments
10/15/2009 1:39 PM EDT
Figure 1 shows the forward converter power stage. This converter operates by transformer-coupling the input voltage into the secondary circuit where it's rectified and filtered. A snubber is often needed when D2 is forced to commutate off through a low impedance circuit formed by the reflected primary voltage and the transformer's leakage inductance. D2 may be a silicon p-n diode with a reverse recovery charge that must be depleted before it turns off. This loads up excess current in the leakage inductance, which results in high-frequency ringing and excess diode voltage. A similar situation exists for Schottky diodes due to their large junction capacitance, and even for synchronous rectifiers due to their turn-off delay times.

Figure 2 shows some of the circuit waveforms, the top trace is the drain voltage of Q1, the middle is the voltage at the junction of D1 and D2, and the bottom is the current through D1. In the top trace, you can see as Q1 turns on, its drain voltage is reduced below the input voltage, which forces the diode D1 current to increase. If D2 has no reverse recovery charge, the junction voltage rises when the D1 current equals the output current. Since it has a reverse recovery charge, the D1 current increases further, which begins to deplete the charge. Once the charge is depleted, the diode turns off, causing the increased junction voltage to increase. Note that the current continues to increase until the junction voltage equals the reflected input voltage because there's a positive voltage across the leakage inductance. While it is increasing, this current is charging parasitic capacitances and leads to further ringing and losses in the circuit.

These ringing waveforms may be deemed unacceptable as they may cause an EMI issue, or they may put unacceptable voltage stresses on the diode. An RC snubber across D2 can reduce the ringing substantially with little impact on efficiency. You can find the ring frequency with the following expression:

But how do you know what the values of L and C are in your circuit? The trick is to lower the ring frequency by adding a known capacitance across D2. You then have two equations and two unknowns. You can make it even easier on yourself if you add just enough capacitance to halve the ring frequency. For half the frequency, you need a total capacitance that's four times the parasitic capacitance that you started with. Then, simply divide the added capacitance by three to get the parasitic capacitance.




Comments
alabie
10/21/2009 5:49 AM EDT
In figure2~4,"D2 current" should be "D1 current",right?
In your example,parasitic capacitance is 150pF,Csnubber is 470pF,but you use 150pF to calculate Rsnubber,why?
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optoeng
10/22/2009 7:05 PM EDT
Have used this procedure for years and can recommend. However, begin by making sure that you've minimized all areas in high di/dt loops. Don't even think about adding snubbers or even building the circuit until you understand this. Then, you'll find your ring frequencies are high, so snubbing components and power dissipation can be small. Then, make sure that the snubbing circuit itself has minimal loop area.
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